Question

In an isobaric process, the ratio of heat supplied to the system (dQ)
and work done by the system (dW)
for diatomic gas is [AFMC 2002]
A) 1 : 1 B) 7 : 2 C) 7 : 5 D) 5 : 7

Answer 1

in an isobaric process the ratio will be A 1:1

Answer 2

Work done by the system (dW)  for diatomic gas is 7:2.

Option (B).

Explanation:

• The isobaric process is a process which involves the thermodynamic principle.

• This makes the pressure in the process of the reaction as constant so that there will be no external or even internal effect on the reaction and their compounds due to pressure.

• As the pressure is constant in the Isobaric process, the value of the dQ is equal to $\left \frac72$ R and the value of dW is equal to R.  

• So the ratio of dQ and dR will be$\left \frac72$ R:R which finally gives the result as 7:2.

       dQ = nCpdt

       And work done is

       dW = nRdT

Also, specific heat for at constant pressure,

        $C_p = \left \frac72 R$

        Therefore ratio of heat supplied to the system is

        $\left(\frac{d Q}{d W}\right)=\frac{n C p d T}{n R d T}=\frac{C p}{R}$

       $=\frac{7 R}{2 R}=\frac{7}{2}$.

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