To calculate the amount of work done in joules during reversible isothermal expansion of an ideal gas, the volume must be expressed in [KCET (Med.) 2001]
A) {{m}^{3}}
only B) d{{m}^{3}}
only C) c{{m}^{3}}
only D) Any one of them
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During reversible isothermal process,
Temperature , T = constant .
so, work done = -PdV
= - nRT/VdV
= - nRT ∫dV/V
= -nRTln[V₂/V₁]
What you see ? , Ratio work done depends upon ratio of Volume .
it means no matter what is the unit of volume ,
Hence, answer is (D) any one of them
Temperature , T = constant .
so, work done = -PdV
= - nRT/VdV
= - nRT ∫dV/V
= -nRTln[V₂/V₁]
What you see ? , Ratio work done depends upon ratio of Volume .
it means no matter what is the unit of volume ,
Hence, answer is (D) any one of them
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