In an isoceles triangle ABC, if AB=AC and AP ⊥ BC then prove that BP=PC
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for the question you have given you will have to use RHS congruence e which means you will take triangles ABP and triangle ACP and then as we know a b is equal to AC and angles APC and a p b are 90degree each so are they are equal to each other and it is the common line so resale triangle abp is congruent triangle ACP by RhS congruency and the BP is equal to PC by CPCT congruent parts of corresponding triangles
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here is your answer ,
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