Question

in an isoceles triangle, the vertex angle is 15° more than each of base angle.

Answer 1

Let the base angle be x

So the vertex angle will be x+15°

ATQ,

2x + (x+15) = 180

or, 3x + 15 = 180

or, 3x = 165

or, x = 55

So the base angles are

55° and the vertex angle

is ( 55+15)° = 70° .

That's it.

Hope it helped ヾ(｡>﹏<｡)ﾉﾞ✧*。