Math, asked by priyanka786, 1 year ago

In an isosceles ΔABC, AD is the median to the unequal side meeting BC at D. DP is the angle disector of ∠ADB and PQ is drawn parallel to BC meeting AC at Q. Then the maeasure of ∠PDQ is

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Answered by karanchauhan

0

Then the PDQ will be 90 degree

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