Math, asked by 856, 8 months ago

In an isosceles right angled DABC , DB =90degree . The value of 2sinAcosA​ is
please jaldi bata dejiye

Answers

Answered by biligiri
0

Answer:

in an isosceles right angle ∆, other two angles are 45°.

therefore sin 45° = cos = 45° = 1/√2

hence 2 sin A cos A = 2×1/√2×1/√2

=> 2/2

=> 1

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