In an isosceles right angled DABC , DB =90degree . The value of 2sinAcosA is
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in an isosceles right angle ∆, other two angles are 45°.
therefore sin 45° = cos = 45° = 1/√2
hence 2 sin A cos A = 2×1/√2×1/√2
=> 2/2
=> 1
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