In an isosceles right angled triangle ABC , if angle A = 90 , FIND value of B and C?
Answers
Answered by
69
GIVEN : angle A=90
: ABC IS AN ISOSCELES TRIANGLE i.e AB=AC
ANGLE B = ANGLE C [angles opp. to equal sides are equal]
WE KNOW ,
SUM OF ALL ANGLES OF TRIANGLE=180
THEREFORE,
A+B+C=180
90+B+B=180 [B=C]
90+2B=180
2B=180-90
2B=90
B=90/2
B=45
SINCE
C=B
C=45
: ABC IS AN ISOSCELES TRIANGLE i.e AB=AC
ANGLE B = ANGLE C [angles opp. to equal sides are equal]
WE KNOW ,
SUM OF ALL ANGLES OF TRIANGLE=180
THEREFORE,
A+B+C=180
90+B+B=180 [B=C]
90+2B=180
2B=180-90
2B=90
B=90/2
B=45
SINCE
C=B
C=45
Answered by
46
Given
ABC is an isosceles right angle triangle
A = 90
B = C ( since ABC is an isosceles triangle)
let B and C be x
A + B + C = 180 (ANGLE SUM PROPERTY)
90 + X +X = 180
2x + 90 = 180
2x = 180-90
2x = 90
x = 90/2
x = 45
therefore B = C = 45
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ABC is an isosceles right angle triangle
A = 90
B = C ( since ABC is an isosceles triangle)
let B and C be x
A + B + C = 180 (ANGLE SUM PROPERTY)
90 + X +X = 180
2x + 90 = 180
2x = 180-90
2x = 90
x = 90/2
x = 45
therefore B = C = 45
Hope U like my answer
if so please mark me as brainelist
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