Question

Length,breadth and height of a room is 8m,6m,4m respectively find the length of diagonal of a room and the area of four walls of room

Answer 1

So to find the area of walls of a room we will calculate it by this formula
         Area of rectangle=l*b
                                    =2(8*4)+2(6*4)
                                    =64+48
 Area of the four walls =112 m^2

Diagonal (c)^2= a^2 + b^2 (Pythagoras theorem)
                       = (8)^2 + (6)^2
                       = 64 + 36
              (c)^2 = 100
                    c = square root  of 100
                    c = 10 m
Therefore the diagonal is of 10 m .

Answer 2

Answer:

Step-by-step explanation:

Area of rectangle=l*b

                                    =2(8*4)+2(6*4)

                                    =64+48

 Area of the four walls =112 m^2

Diagonal (c)^2= a^2 + b^2 (Pythagoras theorem)

                       = (8)^2 + (6)^2

                       = 64 + 36

              (c)^2 = 100

                    c = square root  of 100

                    c = 10 m

Therefore the diagonal is of 10 m .

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