Question

in an isosceles triangle AB = AC and angle b = 65° which is the shortest side?

Answer 1

BC is the shortest side...

Answer 2

so angle b = angle c = 65 degrees ( since angles opposite to equal sides are equal)

angle a = 180 - 65 - 65 = 50 degrees

since the side opposite to the shortest angle is the shortest. AB is the shortest side.