In an isosceles triangle abc the base ab is produced both ways to p and q such that ap×bq=2ac
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Step-by-step explanation:
Given: ΔABC is an isosceles triangle AC = BC.
We know that,
AP x BQ = AC²
AP x BQ = AC x AC
AP/AC=AC/BQ
AP/AC=BC/BQ
Also, ∠CAB = ∠CBA (equal sides have angles opposite to them)
180 – CAP = 180 – CBQ
∠CAP = ∠CBQ
Therefore, ΔAPC∼ΔBCQ (SAS similarity)
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