Question

in an isosceles triangle ABC, the bisector of angle B and angle C meet at a point O. If angle A =40 degree, then angle BOC=?

Answer 1

angle BOC Will be 110°.
1 . in an isosceles triangle 2 angles are equal so
A+B+C=180°[angle sum prop.]
40°+B+B=180°[since B=B]

40°+2B=180°
2B=180°-40°=140°

B=140°/2=79°

there fore A=40°,B=C=70°

as CO biscets C then OCB=35°. [half of C]
and OBC=35°[half of B]
OCB+OBC+BOC=180°
35°+35°+BOC=180°
70°+BOC=180°
BOC=180°-70°=110°

Answer 2

Answer:

Step-by-step explanation:

I have one in the diagram itself .Some one had done solution that also correct only