Question

Find the equation of straight line joining (4,-3) and the intersection of the straight lines 2x-y+7=0 and x+y-1=0

Answer 1

2x-y+7=0----(1)

x+y-1=0---(2)
add both equations

u can get
3x=-6

x =-6/3

x=-2
plug x value in (2)

-2+y-1=0

y=3

intersecting point (-2,3)

equation of a line passing through (x1 , y1)=(4 ,-3) and (x2, y2)=(-2,3) is

(y- y1 )(x2 - x1)= (y2 - y1)(x-x1)

(y+3)(-2-4)=(3+3)(x-4)

(y+3)(-6)=6(x-4)
-y-3=x-4

0=x+y-4+3

x+y-1=0