In an isosceles triangle,each base angle is four times its vertical angle . Find each angle of the triangle .
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Answer:
Let vertical angle of an isosceles triangle = x
∴ Each base angle = 4x
∴ x + 4x + 4x = 180°
(Sum of angles of a triangle)
⇒ 9x = 180° ⇒ x = 180°/9 = 20°
∴ Vertical angle = 20°
and each of the base angle = 4x
= 4 x 20° = 80°
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