Question

In an isosceles triangle each of the base angle is 5 more than twice the Vertical angle

Answer 1

ISOSCELES TRIANGLE :-

Two sides of an isosceles triangle are equal.

Thus,

The base angles are equal to each other.

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Let the vertical angle be x degrees

As per question :-

Each base angle will be equal to :-

$\boxed{ \boxed{2x + 5}}$

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$\sf{ANGLE\:SUM\:PROPERTY\:OF\:TRIANGLE$

$x + 2x + 5 + 2x + 5 = 180 \\ \\ \\ 5x + 10 = 180 \\ \\ \\ 5(x + 2) = 180 \\ \\ \\ x + 2 = 36 \\ \\ \\ x = 36 - 2 = 34 \\ \\ \\ \boxed{x = 34}$

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Vertical Angle = 34 degrees

Base angles is equal to

$2x + 5 = 2 \times 34 + 5 \\ \\ \\ = 68 + 5 \\ \\ \\ = 73$

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