in an isosceles triangle length of the congruent side is 13 cm and its base is 10 cm find the distance between the vertex opposite the best and the centroid
Answers
Answered by
10
Let AB = AC = 13 cm and BC = 10 cm in isosceles triangle ABC.
Length AD drawn from vertex is given by Pythagoras theorem.
AD = √(AC² - BD²) = √(13² - 5²) = √144 = 12cm
AD joins the vertex A to midpoint D of base BC hence AD is also a median which is divided by the centroid G in the ratio :
A : GS = 2: 1
Distance between A and centroid G of triangle ABC is :
(2/3) × 12 = 8cm
Length AD drawn from vertex is given by Pythagoras theorem.
AD = √(AC² - BD²) = √(13² - 5²) = √144 = 12cm
AD joins the vertex A to midpoint D of base BC hence AD is also a median which is divided by the centroid G in the ratio :
A : GS = 2: 1
Distance between A and centroid G of triangle ABC is :
(2/3) × 12 = 8cm
Answered by
0
Answer:
Step-by-step explanation:
Similar questions