In an isosceles triangle, lengths of two sides are 20 cm and angle between this two sides is 30 degree.find the area
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Given
Length of equal sides =20cm
Angle between then=30°
Area of isosceles triangle =1/2 X product of two sides x sine of included angle
A=1/2xa²xsin@
=1/2x20x20xsin30
=10x20 sin30
=10x20x1/2 [sin30=1/2=.5]
=100cm²
Area =100cm²
Length of equal sides =20cm
Angle between then=30°
Area of isosceles triangle =1/2 X product of two sides x sine of included angle
A=1/2xa²xsin@
=1/2x20x20xsin30
=10x20 sin30
=10x20x1/2 [sin30=1/2=.5]
=100cm²
Area =100cm²
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