Question

In an isosceles triangle,prove that the bisectors of the base angles meeting the opposite sides are equal

Answer 1

Answer:

Here ABC is an isocelous triangle with angle A= angle BMC and NB are the angle bisectorsSo now we observe triangle (MBC) and triangle(NBC)

1) BC = BC2) ang(MBC) = ang(NCB)3) ang(NBC) = ang(MCB)

so by ASA congruency condition the triangles are congruentand henceBN = CM.... .

plzzz like & mark brailist