in an isosceles triangle the base is twice large as vertex angle find the angles of the triangle
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let the vertex angle be of x°
then, base angle =2x° and 2x°
Now, by A.S.P
2x°+2x°+x°=180°
5x°=180
x=36°
so,the base angles = 72°and72°
and vertex angle=36°
hope it helps you.
then, base angle =2x° and 2x°
Now, by A.S.P
2x°+2x°+x°=180°
5x°=180
x=36°
so,the base angles = 72°and72°
and vertex angle=36°
hope it helps you.
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