in an isosceles triangle the vertex angle is 110° . find the exterior angle adjacent to either of the base angle
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Let x be the exterior angle (in degrees).
Then the exterior angle is equal to the sum of the two non-adjacent interior angles.
x+45=180 (sum of adjacent angles forming a straight line)
x=180−45=135 degree ⇒ exterior angle.
Interior angle: sum of the angles inside =180
The 2 base angles of an isosceles triangle are equal, so we'll represent each as z.
z+z+45=180
2z=180−45
2z=135
z=67.5 degree ⇒ interior angle.
So, interior angle =67.5 degree, exterior angle =135 degree.
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