in an isosceles triangle the vertical angle is 24° more than each of its base angle find all the angles of the triangle
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2
let one base angle = x
total vertical angle= x+24
as sum of all angles of an triangle is 180 so
x+x+24+x= 180
3x= 156
x= 52
total vertical angle= x+24
as sum of all angles of an triangle is 180 so
x+x+24+x= 180
3x= 156
x= 52
Answered by
1
let base angle = x
In an isosceles triangle opposite angle are equal because opp angles of equal side are equal
now x + x + 24° = 180° ( Angle sum property)
so 2x = 180 - 24 = 156
x = 156/2 = 78°
Thus base angles = 78°
and vertical angle = 24°
In an isosceles triangle opposite angle are equal because opp angles of equal side are equal
now x + x + 24° = 180° ( Angle sum property)
so 2x = 180 - 24 = 156
x = 156/2 = 78°
Thus base angles = 78°
and vertical angle = 24°
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