in an matic progression if the first term is 8 and the common difference is 4 then the 9th term of an ap is
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Answered by
0
Answer:
Given A.P is
1,−2,−5,−8,....
hence the common difference is given by d=a
n+1
−a
n
by putting n=1 in above equation
d=a
2
−a
1
=(−2)−(1)
d=(−2−1)
d=−3
first term of this A.P is
a
1
=1
the nth term of this A.P is given by
a
n
=a
1
+(n−1)d
⟹a
n
=1+(n−1)(−3)
⟹a
n
=1−3n+3
⟹a
n
=4−3n….eq(1)
finding next four terms of A.P
1) for finding the 5th term of sequence (a
5
) put n=5 in eq(1)
⟹a
5
=4−3×5
⟹a
5
=4−15
⟹a
5
=−11
Step-by-step explanation:
take this sum as example and do the sum friend
Answered by
1
Answer:
a9=40
Step-by-step explanation:
an=a+(n-1)d
a9=8+(9-1)4
a9=8+(8)4
a9=8+32
a9=40
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