In an object of 10 cm height is placed at a distance of 36cm from a concave mirror of focal length 12 cm.Find the position,nature and height of the image.
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given h2(height of object)=10cm
u=-36cm
f=-12cm
we know 1/f=1/v+1/u
therefore 1/v=1/f-1/u
(-1/12)-(-1/36)
=-18cm
v=-18cm
image is real and inverted
now m=-v/u=h1/h2
therefore h1=5cm
hope it helps
mark as branliest plz
as u can see in the diagram , the values in the right hand side are taken as -ve and those on left hand side are taken as +ve
u=-36cm
f=-12cm
we know 1/f=1/v+1/u
therefore 1/v=1/f-1/u
(-1/12)-(-1/36)
=-18cm
v=-18cm
image is real and inverted
now m=-v/u=h1/h2
therefore h1=5cm
hope it helps
mark as branliest plz
as u can see in the diagram , the values in the right hand side are taken as -ve and those on left hand side are taken as +ve
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Anshika1352:
thank u astha
can you tell me why the f is negative
sure
thanks
plz tell me fast
concave mirrors are spherical mirrors
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