Physics, asked by ssaleharaffath, 6 months ago

In an orbit of radius 0.5 Aº an electron revolves
with a frequency of 6.25 x 10^15 Hz. The magnetic
induction field at its centre is
1) 4 PI tesla
2) 2PI tesla
3) 4 tesla
4) 2 tesla​

Answers

Answered by piyushkant081
10

Answer:

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Explanation:

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Answered by Sahil3459
2

Answer:

The magnetic induction field at its centre will be 4 PI tesla (4πT).

Explanation:

In the process of electromagnetic induction, a conductor is placed in a certain location while the magnetic field changes or the magnetic field is stationary while the conductor is moving.

Given that:

Revolutions per seconds  = 6.25 × 10¹⁵

So the total current will be = 6.25 × 10¹⁵ × 1.6 × 10⁻¹⁹

= 10⁻³ A

Now the magnetic induction will be:

B = 4π × 10⁷ × 10⁻⁷

B = 4πT

The process of creating an electric current using a magnetic field is known as electromagnetic induction. It happens anytime a magnetic field and electric conductor travel in such a way that the conductor crosses magnetic field lines of force.

Thus, the process by which a magnetic material gains magnetism when a magnet is placed close to it is known as magnetic induction.

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