Question

in an orchard the heights of some trees are recorded as shown in the table given below: Heights of trees No. of trees (in cm) 150 153 7 7 154 157 158-161 162 -165 15 10 166 169 5 170 - 173 6 Convert it into a continuous grouped frequency distribution and using it answer the following questions: (i) Limits of third class will change to (a) 158.5 - 162.5 (b) 158.5 - 161.5 (c) 157.5 - 161.5 (d) 157.5 160.5 (ii) In which interval would 153.5 be included? (a) first (b) second (c) third (d) none of these (iii) What is the class mark of fourth class interval (a) 162 (b) 165 (c) 163.5 (d) none of these (iv) what is the difference between upper limits of the first and fifth class interval ? (a) 10 (b) 12 (c) 14 (d) 16 (v) what is the range of given data (a) 22 (b) 23 (c) 24 (d) 25 ​

Answer 1

Answer:

Refer the attachment for your answer.

just touch both the attachments.

Answer 2

Converting into continuous grouped frequency,

$\sf \fbox \purple{upper \: limit \: - lower \: limit \: of \: next \: class }$

• 153 is upper limit and 154 is Lower limit of 2nd class.

153 - 154 = 1

• Now, Add half of 1 means 0.5 in 153, and subtract 0.5 into 154.

The results are, 153.5 and 153.5

* 157 - 158 = 1

* 157.5 and 157.5

(apply the Same process to all)

• 149.5 - 153.5 7

• 153.5 - 157.5 7

• 157.5 - 161.5 15

• 161.5 - 165.5 10

• 165.5 - 169.5 5

• 169.5 - 173.5 6

i) c} 157.5 - 161.5

ii) ----

iii) ----

iv) d} 16

v) subtract lowest value into the greatest one.