Question

in an triangle abc right angled at b,ab=6units and bc = 8units then find the value of sinA*cosC +cosA*sinC

Answer 1

B=90°
A+C=90°
SinA cosC+cosA sinC=sin(A+C)
=sin 90°=1

Answer 2

triplets
6..8... 10
sinA= 8/10
cosA= 6/10
cosC= 8/10
SinC= 6/10
64/10+36/10
10 answer
sin@= p/h
cos@B/h
base-b
hypotenuse-h
perpendicular- P