Question

In an triangle PQR P=(2x+10) degree Q=(x+70) degrees and R=(2x+20) degrees find the value of X

A= 16 degrees
B= 17 degrees
C= 18 degrees
D= none of these


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Answer 1

$\huge{\boxed{\rm{\red{Question}}}}$

In a triangle PQR P = (2x+10) degree Q = (x+70) degrees and R = (2x+20) degrees find the value of x.

A = 16 degrees

B = 17 degrees

C = 18 degrees

D = None of these

$\huge{\boxed{\rm{\red{Answer}}}}$

${\bigstar}\large{\boxed{\sf{\green{Given \: that}}}}$

Triangle = PQR

Value of Angle P = ( 2x + 10 )°

Value of Q = ( x + 70 )°

Value of R = ( 2x + 20 )°

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

The value of x.

${\bigstar}\large{\boxed{\sf{\blue{Solution}}}}$

The value of x = 16°

${\bigstar}\large{\boxed{\sf{\purple{Compulsory \: to \: know}}}}$

$\large\pink{\texttt{Sum of all angles of triangle ↓}}$

$\large\gray{\texttt{180°}}$

$\large\pink{\texttt{We also write triangle as ∆}}$

$\large\green{\texttt{∆ have 3 sides only}}$

$\large\orange{\texttt{So, we write sum of angle of ∆ as}}$

$\large\red{\texttt{a + b + c = 180°}}$

$\large\purple{\texttt{We also write angle as < }}$

${\bigstar}\large{\boxed{\sf{\pink{Full \: solution}}}}$

$\large\red{\texttt{Substituting the values}}$

$\mapsto a + b + c = 180°$

$\mapsto ( 2x + 10 )° + ( x + 70 )°+ ( 2x + 20 )° = 180°$

$\mapsto 2x + 10 + x + 70 + 2x + 20 = 180°$

$\mapsto 2x + x + 2x + 10 + 70 + 20 = 180°$

$\mapsto 5x + 100 = 180°$

$\mapsto 5x = 180 - 100$

$\mapsto 5x = 80°$

$\mapsto x = 80/5$

$\mapsto x = 16°$

$\large{\boxed{\boxed{\sf\green{16° \: is \: the \: Answer}}}}$

Thank you :)

$\large{\boxed{\boxed{\sf\red{@Priya97O \: ♡@Aditya97O}}}}$

Answer 2

Answer:

In an triangle PQR P=(2x+10) degree Q=(x+70) degrees and R=(2x+20) degrees find the value of X

A= 16 degrees

B= 17 degrees

C= 18 degrees

D= none of these

Don't spam!!

only Quality answer