In an university, out of 100 students 15 offered Mathematics only;
12 offered statistics only; 8 offered only Physics; 40 offered Physics
and Mathematics; 20 offered Physics and Statistics; 10 offered
Mathematics and Statistics, 65 offered Physics. Find the number of
students who (i) Offered Mathematics (ii) Offered Statistics (iii)
Did not offer any of the above three subjects
Answers
Answer:
Step-by-step explanation:
Let the set of students who offered mathematics, statistics and physics be M, S and P respectively. Let a be number of students who offered all 3 subjects. So we get
40 – a + a + 20 – a + 8 = 65
So 68 – a = 65
A = 3
Now students who offered Mathematics
15 + 10 – a + a + 40 – a
65 – a
65 – 3 = 62
Now students who offered Statistics
12 + 10 – a + a + 20 – a
42 – a
42 – 3 = 39
Now students who offered any of three subjects are
15 – 12 + 8 + 10 – a + 40 – a + 20 – a + a
105 – 2 a
105 – 2 x 3
105 – 6
= 99
So number of students who did not offer any subjects were 100 – 99 = 1
Answer:
Let the set of students who offered mathematics, statistics and physics be M, S and P respectively. Let a be number of students who offered all 3 subjects. So we get
40 – a + a + 20 – a + 8 = 65
So 68 – a = 65
A = 3
Now students who offered Mathematics
15 + 10 – a + a + 40 – a
65 – a
65 – 3 = 62
Now students who offered Statistics
12 + 10 – a + a + 20 – a
42 – a
42 – 3 = 39
Now students who offered any of three subjects are
15 – 12 + 8 + 10 – a + 40 – a + 20 – a + a
105 – 2 a
105 – 2 x 3
105 – 6
= 99
So number of students who did not offer any subjects were 100 – 99 = 1
MARK THE OTHER ONE THE MOST BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!