In angle ABC ,AB=AC A=2x and B=x+10 find the measure of all angles of ABC
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Answer:
∠A = 80° , ∠B = 50° and ∠C = 50°
Step-by-step explanation:
In the given triangle AB = AC
Therefore ∠C = ∠B ( Angles opposite to congruent sides )
We know that sum of all measures of a triangle is 180°
So ∠A + ∠B + ∠C = 180°
2x + x + 10 + x + 10 = 180 ( substituted C = x + 10 since ∠C = ∠B )
4x = 180 - 20
4x = 160
x = 40
So ∠A = 2x = 2 x 40 = 80°
∠C = ∠B = x + 10 = 40 + 10 = 50°
Hope this will help and mark me as brainliest if this helped you.
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