Question

in angle ABC, angle B=90and BD is perpendicular to AC. CE bisects angle C. if angleA=48,find angle DMC and angle BEM​

Answer 1

Step-by-step explanation:

In △ABC, AD bisects ∠A

∴   ABAC=BDDC

⇒  cb=BDDC

⇒  cb+1=BDDC+1         [ Adding 1 to both sides ]

⇒  cb+c=BDDC+BD

⇒  cb+c=BDBC       [ DC+BD=BC ]

⇒  cb+c=BDa

∴   BD=b+cac         [ Hence proved ]

Similarly since AD bisects ∠A.

∴  ACAB=DCBD

⇒  b

Answer 2

Answer:

69°,69°

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