in angle abc,c=2b=a+b+20°
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In triangle ABC,
c = 2b = a+b+20
So, 2b = a+ b+20
2b-b = a+20
b = a+20........................(i)
c = a+b+20
c = a+(a+ 20)+20..............(using i)
c = 2a + 40...............................(ii)
By using Angle sum property of triangles,
a+b+c = 180
a+a+20+2a+40=180 ..................(using i and ii)
4a+60= 180
4a =180-60 = 120
∴a = 120/4 =30
b= a+20 = 30+20 = 50
c= 2a+40= 60+40 =100
c = 2b = a+b+20
So, 2b = a+ b+20
2b-b = a+20
b = a+20........................(i)
c = a+b+20
c = a+(a+ 20)+20..............(using i)
c = 2a + 40...............................(ii)
By using Angle sum property of triangles,
a+b+c = 180
a+a+20+2a+40=180 ..................(using i and ii)
4a+60= 180
4a =180-60 = 120
∴a = 120/4 =30
b= a+20 = 30+20 = 50
c= 2a+40= 60+40 =100
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