in angle ABC, CB=90° AB=8cm, BC=6 cm and AC=10cm 1) sinA
2) cosA
3)sin 2A+cos 2A
4) tanA
5) sec2-tan2A
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Answer:
sinA = 6/10 cm.
cosA = 8/10 cm.
sin2A + cos2A = 6/5 + 8/5 = 14/5.
tanA = 6/8 = 3/4
sec2A- tan2A = 10/4 - 3/2 = 10-6/4 = 4/4 =1
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