Question

In angle pqr, right-angled at q, pr+qr=25cm and pq=5cm. determine the values of sin p, cos p, tan p, cosec p , sec p , cot p

Answer 1

Answer:

⇒PQ=5cm

⇒PR+QR=25cm

⇒PR=25−QR

Now, In △PQR

⇒(PR)

2

=PQ

2

+QR

2

⇒(25−QR)

2

=5

2

+QR

2

⇒625+QR

2

−50QR=25+QR

2

⇒50QR=600

⇒QR=12cm

⇒PR=25−12=13cm

∴sinP=

PR

QR

=

13

12

,cosP=

PR

PQ

=

13

5

,tanP=

PQ

QR

=

5

12

Hence, the answers are sinP=

13

12

,cosP=

13

5

,tanP=

5

12

.