Question

in any quadrilateral ABCD, prove that sin(A+B)+sin(C+D)=0​

Answer 1

Answer:

refer to the attachment

Answer 2

Answer:

Follow me

Step-by-step explanation:

in any quadrilatera

A+B+C+D= 360°

=>A+B=360-(C+D)

=>sin(A+B)=sin[360-(C+D)]

=>sin(A+B)=-sin(C+D)

=>sin(A+B)+sin(C+D)=0

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