in any quadrilateral ABCD, prove that sin(A+B)+sin(C+D)=0
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refer to the attachment
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Step-by-step explanation:
in any quadrilatera
A+B+C+D= 360°
=>A+B=360-(C+D)
=>sin(A+B)=sin[360-(C+D)]
=>sin(A+B)=-sin(C+D)
=>sin(A+B)+sin(C+D)=0
/showed/
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