In any regular polygon of n sides, prove that each of its angle of its angles measure (n-2)by n into 180
![(n - 2)by n \times 180 (n - 2)by n \times 180](https://tex.z-dn.net/?f=%28n+-+2%29by+n++%5Ctimes+180)
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(n-2)×180 is the sum of interior angles of a n sides polygon.In a regular polygon ,interior angles are equal,exterior angle are equal.
Therefore:-
=)side × measure of each angle=sum of interior angles.(since it is a regular polygon and all the angles are equal)
=)n×measure of each angle=(n-2)×180
=)measure of each angle=(n-2)÷n×180
Therefore:-
=)side × measure of each angle=sum of interior angles.(since it is a regular polygon and all the angles are equal)
=)n×measure of each angle=(n-2)×180
=)measure of each angle=(n-2)÷n×180
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