Question

In any triangle ABC, if ZC = 90', AC = 4 unit, BC = 3, find AB.​

Answer 1

Answer:

In ∆ABC AS C=90°

WE CAN APPLY PYTHAGORAS THEORM

(AC)^2+(BC)^2=(AC)^2

(3)^2+(4)^2=(AC)^2

9+16=(AC)^2

25=(AC)^2

AC=√25

AC =5 UNITS

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Answer 2

Answer:

AB = 5 units

Step-by-step explanation:

angle C is 90°

ABC is a right angle triangle

hypotenuse is AB

AC and BC are sides

by Pythagoras theorem

${hyp}^{2} = {adj}^{2} + {opp}^{2} \\ {hyp}^{2} = {4}^{2} + {3}^{2} \\ {hyp}^{2} = 16 + 9 \\ {hyp}^{2} = 25 \\ hyp \: = \sqrt{25} \\ hyp = 5$

therefore AB = 5 units