In any triangle if a, b, c, are the lengths of three sides of a triangle. St s-a =7 s-b =5 s-c =3. Then perimeter of ∆ is _______.
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perimeter of triangle=sum of its side
p=a+b+c and p=2s so s=p/2-------1,where s is semi perimeter...
as per question s-a+s-b+s-c=15
so 3s-(a+b+c)=15
3s-2s=15........from 1
s=15
p=2s=15×2=30.....your required answer thank you...
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