In AP Pth term q and Q th term p than P T the sum of P+Q is 1/2 (p+q)(p+q+1)
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a+(p-1)d=q
a+(q-1)d=p
It implies d=-1, a=p+q-1
Sum of p+q terms =(p+q) /2[2a+(p+q-1)d
(p+q)/2[2(p+q-1)-(p+q-1)=(p+q)/2[p+q-1]
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