Question

in ap the 35th term is 123 and D =4.find the first term?​

Answer 1

${\huge{\bold{\purple{\bigstar{\boxed{\bf{Answer}}}}}}}$

${\bold{\blue{\boxed{\bf{Given}}}}}$

• 35th term = 123
• common diff. = d = 4

${\bold{\blue{\boxed{\bf{To\:find}}}}}$

$\bold{a_{1}}= ???$

${\bold{\blue{\boxed{\bf{ Formulae\:used }}}}}$

$\bold {a_n = a + (n-1)d}$

${\bold{\blue{\boxed{\bf{ SoluTion }}}}}$

$123 = a + (35-1)\times 4$

$123 = a + 34 \times 4$

$123 = a + 136$

$a = 123 - 136$

${\bold{\blue{\boxed{\boxed{\bf{a = -13 }}}}}}$

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$\sf{\bold{\green{\underline{\underline{More\:About\:Arithmetic\:Progression}}}}}$

• An arithmetic progression is a sequence ( series ) of numbers in which each term can be obtained by adding a certain quantity to its preceding term .

• In an AP , the difference between 2 consecutive terms is called its common difference and is denoted by letter d .

• The first term of an AP is denoted by a .

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