in AP the fourth and sixth term are 8 and 14 respectevily find the first term and common difference and sum of the first 20 terms
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Fourth term = a+ 3d =8........1
Sixth term = a+5d =14..........2
Using elimination method in eq 1 and 2
so => -2d = -6
=> d = 3
hence putting d =3 in eq 1
a + 3X3 =8
a =-1
Sn = n/2 (2a +(n-1)d)
S20 =20/2 (2x-1+(20-1)3)
= 10(-2+57)
S20 =550
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