Question

In APQR, right angle at Q, PR + QR = 25cm
and PQ =5cm. Determine the values of sinP
cosP and tanP.​

Answer 1

Solution:

In triangle PQR,

PQ = 5 cm

PR + QR = 25 cm

PR = 25 - QR

By Pythagoras Theorem,

(PR)^2 = (PQ)^2 + (QR)^2

(25 - QR)^2 = (5)^2 + (QR)^2

625 + (QR)^2 - 50 QR = 25 + (QR)^2

625 - 25 = 50 QR

600/50 = QR

QR = 12 cm

PR = 25 - QR

= 25 - 12

= 13 cm

sin P = P/H = PQ/PR = 5/13

cos P = B/H = QR/PR = 12/13

tan P = P/B = PQ/QR = 5/12

Hope you understand it!

Answer 2

These are the values of sinP, cosP, tanP .