Question

In aqueous solution Beryllium Sulphate exist as​

Answer 1

Answer:

Be + HCL = BeCl2 + H2

Be + NaOH = Na2BeO2 + H2

Answer 2

Answer:

In aqueous solution beryllium sulphate exists as [Be(H2O)4]SO4.

Explanation:

From an aqueous solution, BeSO4 (Beryllium sulphate) crystallizes as the tetrahydrate BeSO4.4H2O.

The Be2+ cation in BeSO4 (Beryllium sulphate) is a tiny cation with higher hydration energy, which causes it to hydrate by four water molecules and form a tetrahydrate (BeSO4.4H2O) in an aqueous solution that is extremely soluble in water.

The real structure of BeSO4.4H2O is [Be(H2O)4]SO4, and all four water molecules are coordinated to the Be2+ ion.

The Be(H2O)4]2+ ion has a tetrahedral shape and uses four sp3 hybrid orbitals to accommodate 8 electrons from the four water molecules.

As a result, in an aqueous solution, the [Be(H2O)4]2+ cation and SO24 anion combine to create [Be(H2O)4]SO4.