Question

in arithmetic progression a=4 d=2 sn=108
n=? ​

Answer 1

Answer:

answer is...

Step-by-step explanation:

Sn = n/2 [ a + (n-1 ) d] 108 = n/2 × (4+ 2n - 2) 108 = n/2 × (2 +2n) 108 = n/2 ×2 ( 1 + n) 108 = n + n^2 n^2 + n - 108 = 0 and I hope you can solve now

Answer 2

Answer:

a=4

d=2

sn=108

n=?

Ans:

sn =n/2(2a+(n-1)d)

108=n/2(2×4+(n-1)2)

108=n/2(8+2n-2)

108=n/2(6+2n)

108×2=n(6+2n)

216=6n+2n^2

root 216=2(3n+n)

14.69=2(4n)

7.345=4n

1.83625=n