Question

in atriangle ABC ,right angled at B AB=24,BC=10CM .FIND AC

Answer 1

Answer:

given ab= 24cm , bc= 10 cm

and angle B is right angle

then by Pythagoras theorem

${ac}^{2} = { {ab}^{2} } + {bc}^{2}$

${ac}^{2} = {24}^{2} + {10}^{2}$

${ac}^{2} = 576 + 100$

${ac}^{2} = 676$

${ac} = \sqrt{676}$

$ac = 26$