In below fig, ray OS stand on a line POQ. Ray OR and ray OT are angle bisectors of ∠POS and ∠SOQ respectively. If ∠POS = x, find ∠ROT.
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90 degrees
Step-by-step explanation:
Since ray OS stands on the line POQ. Therefore,
∠POS+∠SOQ=180 ∘
⇒x+∠SOQ=180
⇒∠SOQ=180 ∘ −x
⇒2∠SOT=180 ∘ −x [∵OT is bisector of ∠SOQ]
⇒∠SOT=90 ∘ − 2 x
Now, ∠ROT=∠ROS+∠SOT=
2 x +90 ∘ − 2 x = 90 degrees [∵OR is bisector of ∠POS]
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