In below figure , angle ABC = 69° , angle ACB = 31° , find angle BDC .
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ABC = 69° & ACB = 31°
sum of triangle is 180°
69°+31°= 100°
180°-100°=80°
BDC=80°
sum of triangle is 180°
69°+31°= 100°
180°-100°=80°
BDC=80°
ayman1111:
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Hello mate =_=
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Solution:
∠ABC+∠ACB+∠BAC=180°
⇒69°+31°+∠BAC=180°
⇒∠BAC=180°−69°−31°=80° ........(1)
∠BAC=∠BDC (Angles in the same segment are equal) .......(2)
From (1) and (2), we can say that
∠BDC=80°
hope, this will help you.
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