Question

In bohr's atomic model radius of 1st orbit of hydrogen is 0.053 nm then rdius of 3rd orbit of li2+ is

Answer 1

Answer:

rdius of 3rd orbit of li2+ is 0.159 nm

Answer 2

The radius of the third orbit in $Li^{2+}$ is 0.1587 nm.

Explanation:

Radius of the nth level in hydrogen like atom is given by :

$r_n=\frac{n^2\times 52.9}{Z}pm$

where,

$r_n$ = radius of $n^{th}$ orbit

n = number of orbit

Z = atomic number

We have :

Radius of third orbit in the lithium ion :

n = 3, Z = 3

$r_3=\frac{3^2\times 52.9}{3}=158.7 pm$

1 pm = 0.001 nm

158.7 pm =  158.7 × 0.001 nm = 0.1587 nm

The radius of the third orbit in $Li^{2+}$ is 0.1587 nm.

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