In bohr's series of lines of hydrogen spectrum,the third line the red end corresponds to which one of the following inter-orbit jumps of the electron for bohr's orbit in an atom of hydrogen
a.5 to 2
b.4 to 1
c.6 to 1
d.3 to 2
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Answers
Answered by
228
The correct answer is (a)(5to 2) . here we see red end means it is a part of the visible region and abviously only Balmer series corresponds to the visible region for the Balmer series n1=2 and red end means low energy or third end from this means n2=-5
2(r)5. 3
2(r)4. 2
2(r)3. 1
HOPE THIS HELPS
THANK YOU :))
2(r)5. 3
2(r)4. 2
2(r)3. 1
HOPE THIS HELPS
THANK YOU :))
Answered by
290
☆Hey!!!! Your answer is option "a".
_______________________
◢EXPLAINATION :-
●Since the line in Hydrogen spectrum lies within region that is at Red end.
●Therefore it is corresponds to the Balmer series.
______________________________
☆The line at the Red end suggests that :-
●The 1st line of Balmer series is => n=3 to n=2
●The 2nd line of Balmer series is => n=4 to n=2
●The 3rd line of Balmer series is => n=5 to n=2
____________________________
ᴥThus the answer is => 5 --> 2 = 5 to 2
=====================================
_-_-_-_☆☆_-_-_-_
_______________________
◢EXPLAINATION :-
●Since the line in Hydrogen spectrum lies within region that is at Red end.
●Therefore it is corresponds to the Balmer series.
______________________________
☆The line at the Red end suggests that :-
●The 1st line of Balmer series is => n=3 to n=2
●The 2nd line of Balmer series is => n=4 to n=2
●The 3rd line of Balmer series is => n=5 to n=2
____________________________
ᴥThus the answer is => 5 --> 2 = 5 to 2
=====================================
_-_-_-_☆☆_-_-_-_
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