Math, asked by Surya1509, 7 months ago

In ΔΑΒC, Σα” cos (B-C) =

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Answered by Lovelyfriend

3

ANSWER

LHS=a3cos(B−C)+b3cos(C−A)+c3cos(A−B)

=a2bcosB+a2ccosC+b2acosA+b2ccosC+c2acosA+c2bcosB

=ab(acosB+bcosA)+ac(acosC+ccosA)+bc(bcosC)ccosB)

=ab(c)+ac(b)+bc(a)

=3abc

=RHS

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