In ∆CAB,Seg CD ┴ seg AB,<B= 45º,AD=5,BD=8 and BC=8√2 then find CD and AB.
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Step-by-step explanation:
Given: AD=5cm, BD=8cm, BC=8√2cm
To Find: Value of CD and AB=?
AB=AD+BD
AB=(5+8)cm
AB=13cm
In ∆CDB,
by Pythagoras theorem,
(CD)^2=(CB)^2-(DB)^2
(CD)^2=(8√2)^2-(8)^2
(CD)^2=128-64
(CD)^2=64
CD. =√64cm
CD. =8cm. Answer.
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