In carbon monoxide the carbon nd the oxygen atoms are separated by distance 1.2 annguston .The distance of the center of mass from the carbon atom is
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mass of the C atom = 12 units
mass of the O atom = 16 units
position of the C atom is taken to be origin.
hence,
position of centre of mass : = 1.2* 16 /(12+16)
= mass of the C atom = 12 units
mass of the O atom = 16 units
position of the C atom is taken to be origin.
hence,
position of centre of mass : = 1.2* 16 /(12+16)
= 12*16/28 = 0.69 Angstrom
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mass of the O atom = 16 units
position of the C atom is taken to be origin.
hence,
position of centre of mass : = 1.2* 16 /(12+16)
= mass of the C atom = 12 units
mass of the O atom = 16 units
position of the C atom is taken to be origin.
hence,
position of centre of mass : = 1.2* 16 /(12+16)
= 12*16/28 = 0.69 Angstrom
If you find the solution correct then please approve it & in case of any confusion further please do feel free to write me here. I would be more than happy to help further
If you find the solution correct then please approve it & in case of any confusion further please do feel free to write me here. I would be more than happy to help further
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